两个json数组合并去重，以及删除某一项元素
let ha = [
{id:'H',name:'3'},
{id:'A',name:'6'},
{id:'B',name:'14'},
{id:'C',name:'60'}
];

let hb= [
{id:'H',name:'2'},
{id:'A',name:'6'},
{id:'B',name:'16'},
{id:'N',name:'2'},
{id:'C',name:'19'}
];

// 合并两个json数组，并去重;

ha= Object.assign([], ha, hb);
console.log('ha',ha);

// [
{id:'H',name:'2'},
{id:'A',name:'6'},
{id:'B',name:'16'},
{id:'N',name:'2'},
{id:'C',name:'19'}
];


// 去除json数组中的某一项

ha.splice(3, 1);
console.log('ha',ha);

// [
{id:'H',name:'2'},
{id:'A',name:'6'},
{id:'B',name:'16'},
{id:'C',name:'19'}
];
let ha = [
{id:'H',name:'3'},
{id:'A',name:'6'},
{id:'B',name:'14'},
{id:'C',name:'60'}
];

let hb= [
{id:'H',name:'2'},
{id:'A',name:'6'},
{id:'B',name:'16'},
{id:'N',name:'2'},
{id:'C',name:'19'}
];

// 合并两个json数组，并去重;

ha= Object.assign([], ha, hb);
console.log('ha',ha);

// [
{id:'H',name:'2'},
{id:'A',name:'6'},
{id:'B',name:'16'},
{id:'N',name:'2'},
{id:'C',name:'19'}
];


// 去除json数组中的某一项

ha.splice(3, 1);
console.log('ha',ha);

// [
{id:'H',name:'2'},
{id:'A',name:'6'},
{id:'B',name:'16'},
{id:'C',name:'19'}
];注：一、Object.assign()方法,浅拷贝、对象属性的合并（数组是对象）二、splice()方法在W3C中我们可以查到有关于splice()的描述：详情可以 查看这篇文章：https:///article/43046.htmhttps:///article/43046.htmarrayObject.splice(index, howmany, item1, ....., itemX) 方法向/从数组中添加/删除项目，然后返回被删除的项目。参数1：index 为插入添加或（和）删除的起始位置；参数2：howmany 指定从数组中添加/删除的元素个数；参数3：item1, ....., itemX 可选，选择添加操作时填入，表示需要添加的元素。参考：JS中彻底删除json对象组成的数组中的元素JS中彻底删除json对象组成的数组中的元素js删除json中指定的元素JS删除数组里的某个元素方法JS删除数组里的某个元素方法下面是其他网友的补充下面是其他网友的补充将两个json数组合并将两个json数组合并
var str1=[{name:"11",age:11}];
var str2=[{name:"22",age:22}];

var str3 = [];

for (var i = 0; i < str1.length; i++) {

str3.push(str1[i]);
}

for (var i = 0; i < str2.length; i++) {

str3.push(str2[i]);
}

--------------

var str3 = str1.concat(str2);
var str1=[{name:"11",age:11}];
var str2=[{name:"22",age:22}];

var str3 = [];

for (var i = 0; i < str1.length; i++) {

str3.push(str1[i]);
}

for (var i = 0; i < str2.length; i++) {

str3.push(str2[i]);
}

--------------

var str3 = str1.concat(str2);本质上是数组，用合并数组的方法来进行合并。JS实现JSON数组合并和去重JS实现JSON数组合并和去重有两个json数组demo1和demo2
var demo1 = [{"id": 0, "name": "牛肉"},{"id": 1,"name": "羊肉"}];
var demo2 = [{"id": 2, "name": "牛肉"},{"id": 3,"name": "鱼肉"},{ "id": 4,"name":"鸡肉"}];
var demo1 = [{"id": 0, "name": "牛肉"},{"id": 1,"name": "羊肉"}];
var demo2 = [{"id": 2, "name": "牛肉"},{"id": 3,"name": "鱼肉"},{ "id": 4,"name":"鸡肉"}];数组合并
var totalDemo = demo1.concat(demo2);
console.log(totalDemo); //[{"id": 0, "name": "牛肉"},{"id": 1,"name": "羊肉"},{"id": 2, "name": "牛肉"},{"id": 3,"name": "鱼肉"},{ "id": 4,"name":"鸡肉"}]
var totalDemo = demo1.concat(demo2);
console.log(totalDemo); //[{"id": 0, "name": "牛肉"},{"id": 1,"name": "羊肉"},{"id": 2, "name": "牛肉"},{"id": 3,"name": "鱼肉"},{ "id": 4,"name":"鸡肉"}]数组合并用的是concat方法，它可以用于字符串之间的连接和数组之间的连接。数组去重数组去重上面已经得到合并的数组 totalDemo ，去掉name属性是一样的json对象
var temp = {};
//用于name判断重复
var result = []; //最后的新数组

totalDemo.map(function (item, index) {

if(!temp[item.name]){

result.push(item);

temp[item.name] = true;

}
});

console.log(result);//[{"id": 0, "name": "牛肉"},{"id": 1,"name": "羊肉"},{"id": 3,"name": "鱼肉"},{ "id": 4,"name":"鸡肉"}];

var temp = {};
//用于name判断重复
var result = []; //最后的新数组

totalDemo.map(function (item, index) {

if(!temp[item.name]){

result.push(item);

temp[item.name] = true;

}
});

console.log(result);//[{"id": 0, "name": "牛肉"},{"id": 1,"name": "羊肉"},{"id": 3,"name": "鱼肉"},{ "id": 4,"name":"鸡肉"}];
map方法：按照原始数组元素顺序依次处理元素。可以在map方法里面输入console.log(item)打印看下，它会把数组中的对象依次打印出来。